PSLEBobby pushes two rods, M and N, straight into the ground until the length of each rod that is above the ground is the same.
18 of M and
112 of N are in the ground. The length of M in the ground is 32 cm longer than the length of N in the ground. What is the total length of rods M and N?
Fraction of Rod M above ground
= 1 -
18 =
78 Fraction of Rod N above ground
= 1 -
112 =
1112 Heights of Rods M and N above ground are the same.
78 M =
1112 N
7788 M =
7784 N
Length of Rod M more than length of Rod N
= 88 u - 84 u
= 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Total length of Rods M and N
= 88 u + 84 u
= 172 u
= 172 x 8
= 1376 cm
Answer(s): 1376 cm