PSLESam pushes two rods, V and W, straight into the ground until the length of each rod that is above the ground is the same.
14 of V and
16 of W are in the ground. The length of V in the ground is 8 cm longer than the length of W in the ground. What is the total length of rods V and W?
Fraction of Rod V above ground
= 1 -
14 =
34 Fraction of Rod W above ground
= 1 -
16 =
56 Heights of Rods V and W above ground are the same.
34 V =
56 W
1520 V =
1518 W
Length of Rod V more than length of Rod W
= 20 u - 18 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total length of Rods V and W
= 20 u + 18 u
= 38 u
= 38 x 4
= 152 cm
Answer(s): 152 cm