PSLEDavid pushes two rods, F and G, straight into the ground until the length of each rod that is above the ground is the same.
18 of F and
111 of G are in the ground. The length of F in the ground is 24 cm longer than the length of G in the ground. What is the total length of rods F and G?
Fraction of Rod F above ground
= 1 -
18 =
78 Fraction of Rod G above ground
= 1 -
111 =
1011 Heights of Rods F and G above ground are the same.
78 F =
1011 G
7080 F =
7077 G
Length of Rod F more than length of Rod G
= 80 u - 77 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Total length of Rods F and G
= 80 u + 77 u
= 157 u
= 157 x 8
= 1256 cm
Answer(s): 1256 cm