PSLEPeter pushes two rods, W and X, straight into the ground until the length of each rod that is above the ground is the same.
18 of W and
110 of X are in the ground. The length of W in the ground is 16 cm longer than the length of X in the ground. What is the total length of rods W and X?
Fraction of Rod W above ground
= 1 -
18 =
78 Fraction of Rod X above ground
= 1 -
110 =
910 Heights of Rods W and X above ground are the same.
78 W =
910 X
6372 W =
6370 X
Length of Rod W more than length of Rod X
= 72 u - 70 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Total length of Rods W and X
= 72 u + 70 u
= 142 u
= 142 x 8
= 1136 cm
Answer(s): 1136 cm