PSLEHoward pushes two poles, D and E, straight into the ground until the length of each pole that is above the ground is the same.
16 of D and
18 of E are in the ground. The length of D in the ground is 12 cm longer than the length of E in the ground. What is the total length of poles D and E?
Fraction of Pole D above ground
= 1 -
16 =
56 Fraction of Pole E above ground
= 1 -
18 =
78 Heights of Poles D and E above ground are the same.
56 D =
78 E
3542 D =
3540 E
Length of Pole D more than length of Pole E
= 42 u - 40 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Total length of Poles D and E
= 42 u + 40 u
= 82 u
= 82 x 6
= 492 cm
Answer(s): 492 cm