PSLEBilly pushes two rods, Z and A, straight into the ground until the length of each rod that is above the ground is the same.
13 of Z and
16 of A are in the ground. The length of Z in the ground is 9 cm longer than the length of A in the ground. What is the total length of rods Z and A?
Fraction of Rod Z above ground
= 1 -
13 =
23 Fraction of Rod A above ground
= 1 -
16 =
56 Heights of Rods Z and A above ground are the same.
23 Z =
56 A
1015 Z =
1012 A
Length of Rod Z more than length of Rod A
= 15 u - 12 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Total length of Rods Z and A
= 15 u + 12 u
= 27 u
= 27 x 3
= 81 cm
Answer(s): 81 cm