PSLEIvan pushes two rods, B and C, straight into the ground until the length of each rod that is above the ground is the same.
18 of B and
111 of C are in the ground. The length of B in the ground is 24 cm longer than the length of C in the ground. What is the total length of rods B and C?
Fraction of Rod B above ground
= 1 -
18 =
78 Fraction of Rod C above ground
= 1 -
111 =
1011 Heights of Rods B and C above ground are the same.
78 B =
1011 C
7080 B =
7077 C
Length of Rod B more than length of Rod C
= 80 u - 77 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Total length of Rods B and C
= 80 u + 77 u
= 157 u
= 157 x 8
= 1256 cm
Answer(s): 1256 cm