PSLEBobby pushes two rods, S and T, straight into the ground until the length of each rod that is above the ground is the same.
16 of S and
19 of T are in the ground. The length of S in the ground is 18 cm longer than the length of T in the ground. What is the total length of rods S and T?
Fraction of Rod S above ground
= 1 -
16 =
56 Fraction of Rod T above ground
= 1 -
19 =
89 Heights of Rods S and T above ground are the same.
56 S =
89 T
4048 S =
4045 T
Length of Rod S more than length of Rod T
= 48 u - 45 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Total length of Rods S and T
= 48 u + 45 u
= 93 u
= 93 x 6
= 558 cm
Answer(s): 558 cm