PSLEJack pushes two rods, G and H, straight into the ground until the length of each rod that is above the ground is the same.
16 of G and
110 of H are in the ground. The length of G in the ground is 24 cm longer than the length of H in the ground. What is the total length of rods G and H?
Fraction of Rod G above ground
= 1 -
16 =
56 Fraction of Rod H above ground
= 1 -
110 =
910 Heights of Rods G and H above ground are the same.
56 G =
910 H
4554 G =
4550 H
Length of Rod G more than length of Rod H
= 54 u - 50 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Total length of Rods G and H
= 54 u + 50 u
= 104 u
= 104 x 6
= 624 cm
Answer(s): 624 cm