PSLECarl pushes two rods, D and E, straight into the ground until the length of each rod that is above the ground is the same.
17 of D and
111 of E are in the ground. The length of D in the ground is 14 cm longer than the length of E in the ground. What is the total length of rods D and E?
Fraction of Rod D above ground
= 1 -
17 =
67 Fraction of Rod E above ground
= 1 -
111 =
1011 Heights of Rods D and E above ground are the same.
67 D =
1011 E
3035 D =
3033 E
Length of Rod D more than length of Rod E
= 35 u - 33 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total length of Rods D and E
= 35 u + 33 u
= 68 u
= 68 x 7
= 476 cm
Answer(s): 476 cm