PSLEDylan pushes two rods, Q and R, straight into the ground until the length of each rod that is above the ground is the same.
14 of Q and
16 of R are in the ground. The length of Q in the ground is 8 cm longer than the length of R in the ground. What is the total length of rods Q and R?
Fraction of Rod Q above ground
= 1 -
14 =
34 Fraction of Rod R above ground
= 1 -
16 =
56 Heights of Rods Q and R above ground are the same.
34 Q =
56 R
1520 Q =
1518 R
Length of Rod Q more than length of Rod R
= 20 u - 18 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total length of Rods Q and R
= 20 u + 18 u
= 38 u
= 38 x 4
= 152 cm
Answer(s): 152 cm