PSLEThe figure is made up of two rectangles, ABHF and FGDE, and two right-angled isosceles triangles, BCH and DCG. BA = 9 cm, DE = 5 cm and BH =
j cm. AFE and CHGF are straight lines.
- Find the length of AE in terms of j. Give your answer in the simplest form.
- Find the total area of the figure when j = 16.
(a)
Length HG
= 9 - 5
= 4 cm
Length CH =
j cm (Isosceles triangle)
Length GD
= Length CG
= (
j + 4) cm (Isosceles triangle)
Length AE
=
j +
j + 4
= (2
j + 4) cm
(b)
Area of Rectangle ABFH
= 16 x 9
= 144 cm
2 Length FE
=
j + 4
= 16 + 4
= 20 cm
Area of Rectangle DEFG
= 20 x 5
= 100 cm
2 Area of Triangle BCH
=
12 x 16 x 16
= 128 cm
2 Area of Triangle CDG
=
12 x 20 x 20
= 200 cm
2 Total area of the figure
= 144 + 100 + 128 + 200
= 572 cm
2 Answer(s): (a) (2
j + 4) cm; b) 572 cm
2