PSLEThe figure is made up of two rectangles, NPVT and TURS, and two right-angled isosceles triangles, PQV and RQU. PN = 10 cm, RS = 6 cm and PV =
w cm. NTS and QVUT are straight lines.
- Find the length of NS in terms of w. Give your answer in the simplest form.
- Find the total area of the figure when w = 14.
(a)
Length VU
= 10 - 6
= 4 cm
Length QV =
w cm (Isosceles triangle)
Length UR
= Length CG
= (
w + 4) cm (Isosceles triangle)
Length NS
=
w +
w + 4
= (2
w + 4) cm
(b)
Area of Rectangle NPTV
= 14 x 10
= 140 cm
2 Length TS
=
w + 4
= 14 + 4
= 18 cm
Area of Rectangle RSTU
= 18 x 6
= 108 cm
2 Area of Triangle PQV
=
12 x 14 x 14
= 98 cm
2 Area of Triangle QRU
=
12 x 18 x 18
= 162 cm
2 Total area of the figure
= 140 + 108 + 98 + 162
= 508 cm
2 Answer(s): (a) (2
w + 4) cm; b) 508 cm
2