PSLE
The pie charts show the number of each type of stationery in 2 stationery boxes, E and F. The total number of stationery in Box E is five times the total number of stationery in Box F.

1. Find the percentage of glues in Box E.
2. What fraction of stationery in Box F is glues?
3. The number of glues in Box E is 300. Find the number of glues in Box F.

(a)
^90°_360° = 25% of stationery in Box E

Percentage of foolscaps in Box E = 25%

Percentage of glues in Box E
= 100% - 45% - 25%
= 30%

(b)
Percentage of glues in Box F
= 100% - 60% - 20%
= 20%

Fraction of stationery in Box F that is glues
= ¹₅

(c)
30% of stationery in Box E = 300
1% of stationery in Box E = 300 ÷ 30 = 10 
100% of the stationery in Box E = 100 x 10 = 1000

Number of stationery in Box F
= 1000 ÷ 5
= 200

100% of stationery in Box F = 200
1% of stationery in Box E = 200 ÷ 100 = 2
20% of stationery in Box E = 20 x 2 = 40  

Number of glues in Box F = 40

Answer(s): (a) 30%; (b) ¹₅; (c) 40