PSLE
The pie charts show the number of each type of stationery in 2 stationery boxes, N and P. The total number of stationery in Box N is four times the total number of stationery in Box P.

1. Find the percentage of correction tapes in Box N.
2. What fraction of stationery in Box P is correction tapes?
3. The number of correction tapes in Box N is 120. Find the number of correction tapes in Box P.

(a)
^90°_360° = 25% of stationery in Box N

Percentage of foolscaps in Box N = 25%

Percentage of correction tapes in Box N
= 100% - 45% - 25%
= 30%

(b)
Percentage of correction tapes in Box P
= 100% - 55% - 25%
= 20%

Fraction of stationery in Box P that is correction tapes
= ¹₅

(c)
30% of stationery in Box N = 120
1% of stationery in Box N = 120 ÷ 30 = 4 
100% of the stationery in Box N = 100 x 4 = 400

Number of stationery in Box P
= 400 ÷ 4
= 100

100% of stationery in Box P = 100
1% of stationery in Box N = 100 ÷ 100 = 1
20% of stationery in Box N = 20 x 1 = 20  

Number of correction tapes in Box P = 20

Answer(s): (a) 30%; (b) ¹₅; (c) 20