PSLEThe pie charts show the number of each type of stationery in 2 stationery boxes, M and N. The total number of stationery in Box M is twice the total number of stationery in Box N.
- Find the percentage of foolscaps in Box M.
- What fraction of stationery in Box N is foolscaps?
- The number of foolscaps in Box M is 240. Find the number of foolscaps in Box N.
(a)
90°360° = 25% of stationery in Box M
Percentage of punchers in Box M = 25%
Percentage of foolscaps in Box M
= 100% - 45% - 25%
= 30%
(b)
Percentage of foolscaps in Box N
= 100% - 70% - 15%
= 15%
Fraction of stationery in Box N that is foolscaps
= 15100
=
320 (c)
30% of stationery in Box M = 240
1% of stationery in Box M = 240 ÷ 30 = 8
100% of the stationery in Box M = 100 x 8 = 800
Number of stationery in Box N
= 800 ÷ 2
= 400
100% of stationery in Box N = 400
1% of stationery in Box M = 400 ÷ 100 = 4
15% of stationery in Box M = 15 x 4 = 60
Number of foolscaps in Box N = 60
Answer(s): (a) 30%; (b)
320; (c) 60