PSLE
The pie charts show the number of each type of stationery in 2 stationery boxes, U and V. The total number of stationery in Box U is twice the total number of stationery in Box V.

1. Find the percentage of foolscaps in Box U.
2. What fraction of stationery in Box V is foolscaps?
3. The number of foolscaps in Box U is 90. Find the number of foolscaps in Box V.

(a)
^90°_360° = 25% of stationery in Box U

Percentage of post-it pads in Box U = 25%

Percentage of foolscaps in Box U
= 100% - 30% - 25%
= 45%

(b)
Percentage of foolscaps in Box V
= 100% - 70% - 15%
= 15%

Fraction of stationery in Box V that is foolscaps
= ³₂₀

(c)
45% of stationery in Box U = 90
1% of stationery in Box U = 90 ÷ 45 = 2 
100% of the stationery in Box U = 100 x 2 = 200

Number of stationery in Box V
= 200 ÷ 2
= 100

100% of stationery in Box V = 100
1% of stationery in Box U = 100 ÷ 100 = 1
15% of stationery in Box U = 15 x 1 = 15  

Number of foolscaps in Box V = 15

Answer(s): (a) 45%; (b) ³₂₀; (c) 15