PSLE
The pie charts show the number of each type of stationery in 2 stationery boxes, H and J. The total number of stationery in Box H is four times the total number of stationery in Box J.

1. Find the percentage of foolscaps in Box H.
2. What fraction of stationery in Box J is foolscaps?
3. The number of foolscaps in Box H is 140. Find the number of foolscaps in Box J.

(a)
^90°_360° = 25% of stationery in Box H

Percentage of punchers in Box H = 25%

Percentage of foolscaps in Box H
= 100% - 40% - 25%
= 35%

(b)
Percentage of foolscaps in Box J
= 100% - 40% - 25%
= 35%

Fraction of stationery in Box J that is foolscaps
= ⁷₂₀

(c)
35% of stationery in Box H = 140
1% of stationery in Box H = 140 ÷ 35 = 4 
100% of the stationery in Box H = 100 x 4 = 400

Number of stationery in Box J
= 400 ÷ 4
= 100

100% of stationery in Box J = 100
1% of stationery in Box H = 100 ÷ 100 = 1
35% of stationery in Box H = 35 x 1 = 35  

Number of foolscaps in Box J = 35

Answer(s): (a) 35%; (b) ⁷₂₀; (c) 35