PSLE
The pie charts show the number of each type of stationery in 2 stationery boxes, T and U. The total number of stationery in Box T is twice the total number of stationery in Box U.

1. Find the percentage of punchers in Box T.
2. What fraction of stationery in Box U is punchers?
3. The number of punchers in Box T is 270. Find the number of punchers in Box U.

(a)
^90°_360° = 25% of stationery in Box T

Percentage of staplers in Box T = 25%

Percentage of punchers in Box T
= 100% - 30% - 25%
= 45%

(b)
Percentage of punchers in Box U
= 100% - 40% - 30%
= 30%

Fraction of stationery in Box U that is punchers
= ³₁₀

(c)
45% of stationery in Box T = 270
1% of stationery in Box T = 270 ÷ 45 = 6 
100% of the stationery in Box T = 100 x 6 = 600

Number of stationery in Box U
= 600 ÷ 2
= 300

100% of stationery in Box U = 300
1% of stationery in Box T = 300 ÷ 100 = 3
30% of stationery in Box T = 30 x 3 = 90  

Number of punchers in Box U = 90

Answer(s): (a) 45%; (b) ³₁₀; (c) 90