PSLE FGHJ and GJKL are rhombuses. HMJ is a straight line.
- Find ∠JGM.
- Find ∠HJK.
(a)
∠GJH
= (180° - 104°) ÷2
= 76° ÷ 2
= 38° (Isosceles triangle)
∠JGM
= 180° - 120° - 38°
= 22° (Angles sum of triangle)
(b)
∠GLK
= 360° - 285°
= 75° (Angles at a point)
∠GJK = ∠GLK = 75° (Rhombus)
∠HJK
= 75° - 38°
= 37°
Answer(s): (a) 22°; (b) 37°