PSLE DEFG and EGHJ are rhombuses. FKG is a straight line.
- Find ∠GEK.
- Find ∠FGH.
(a)
∠EGF
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠GEK
= 180° - 129° - 37°
= 14° (Angles sum of triangle)
(b)
∠EJH
= 360° - 285°
= 75° (Angles at a point)
∠EGH = ∠EJH = 75° (Rhombus)
∠FGH
= 75° - 37°
= 38°
Answer(s): (a) 14°; (b) 38°