PSLE TUVW and UWXY are rhombuses. VZW is a straight line.
- Find ∠WUZ.
- Find ∠VWX.
(a)
∠UWV
= (180° - 108°) ÷2
= 72° ÷ 2
= 36° (Isosceles triangle)
∠WUZ
= 180° - 128° - 36°
= 16° (Angles sum of triangle)
(b)
∠UYX
= 360° - 280°
= 80° (Angles at a point)
∠UWX = ∠UYX = 80° (Rhombus)
∠VWX
= 80° - 36°
= 44°
Answer(s): (a) 16°; (b) 44°