PSLE HJKL and JLMN are rhombuses. KPL is a straight line.
- Find ∠LJP.
- Find ∠KLM.
(a)
∠JLK
= (180° - 96°) ÷2
= 84° ÷ 2
= 42° (Isosceles triangle)
∠LJP
= 180° - 127° - 42°
= 11° (Angles sum of triangle)
(b)
∠JNM
= 360° - 291°
= 69° (Angles at a point)
∠JLM = ∠JNM = 69° (Rhombus)
∠KLM
= 69° - 42°
= 27°
Answer(s): (a) 11°; (b) 27°