PSLE TUVW and UWXY are rhombuses. VZW is a straight line.
- Find ∠WUZ.
- Find ∠VWX.
(a)
∠UWV
= (180° - 102°) ÷2
= 78° ÷ 2
= 39° (Isosceles triangle)
∠WUZ
= 180° - 124° - 39°
= 17° (Angles sum of triangle)
(b)
∠UYX
= 360° - 299°
= 61° (Angles at a point)
∠UWX = ∠UYX = 61° (Rhombus)
∠VWX
= 61° - 39°
= 22°
Answer(s): (a) 17°; (b) 22°