PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 104°) ÷2
= 76° ÷ 2
= 38° (Isosceles triangle)
∠HFL
= 180° - 130° - 38°
= 12° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 295°
= 65° (Angles at a point)
∠FHJ = ∠FKJ = 65° (Rhombus)
∠GHJ
= 65° - 38°
= 27°
Answer(s): (a) 12°; (b) 27°