PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 96°) ÷2
= 84° ÷ 2
= 42° (Isosceles triangle)
∠HFL
= 180° - 128° - 42°
= 10° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 287°
= 73° (Angles at a point)
∠FHJ = ∠FKJ = 73° (Rhombus)
∠GHJ
= 73° - 42°
= 31°
Answer(s): (a) 10°; (b) 31°