PSLE HJKL and JLMN are rhombuses. KPL is a straight line.
- Find ∠LJP.
- Find ∠KLM.
(a)
∠JLK
= (180° - 100°) ÷2
= 80° ÷ 2
= 40° (Isosceles triangle)
∠LJP
= 180° - 121° - 40°
= 19° (Angles sum of triangle)
(b)
∠JNM
= 360° - 287°
= 73° (Angles at a point)
∠JLM = ∠JNM = 73° (Rhombus)
∠KLM
= 73° - 40°
= 33°
Answer(s): (a) 19°; (b) 33°