PSLE HJKL and JLMN are rhombuses. KPL is a straight line.
- Find ∠LJP.
- Find ∠KLM.
(a)
∠JLK
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠LJP
= 180° - 131° - 37°
= 12° (Angles sum of triangle)
(b)
∠JNM
= 360° - 277°
= 83° (Angles at a point)
∠JLM = ∠JNM = 83° (Rhombus)
∠KLM
= 83° - 37°
= 46°
Answer(s): (a) 12°; (b) 46°