PSLE TUVW and UWXY are rhombuses. VZW is a straight line.
- Find ∠WUZ.
- Find ∠VWX.
(a)
∠UWV
= (180° - 104°) ÷2
= 76° ÷ 2
= 38° (Isosceles triangle)
∠WUZ
= 180° - 125° - 38°
= 17° (Angles sum of triangle)
(b)
∠UYX
= 360° - 280°
= 80° (Angles at a point)
∠UWX = ∠UYX = 80° (Rhombus)
∠VWX
= 80° - 38°
= 42°
Answer(s): (a) 17°; (b) 42°