PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 108°) ÷2
= 72° ÷ 2
= 36° (Isosceles triangle)
∠HFL
= 180° - 129° - 36°
= 15° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 299°
= 61° (Angles at a point)
∠FHJ = ∠FKJ = 61° (Rhombus)
∠GHJ
= 61° - 36°
= 25°
Answer(s): (a) 15°; (b) 25°