PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 102°) ÷2
= 78° ÷ 2
= 39° (Isosceles triangle)
∠HFL
= 180° - 124° - 39°
= 17° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 279°
= 81° (Angles at a point)
∠FHJ = ∠FKJ = 81° (Rhombus)
∠GHJ
= 81° - 39°
= 42°
Answer(s): (a) 17°; (b) 42°