PSLE FGHJ and GJKL are rhombuses. HMJ is a straight line.
- Find ∠JGM.
- Find ∠HJK.
(a)
∠GJH
= (180° - 96°) ÷2
= 84° ÷ 2
= 42° (Isosceles triangle)
∠JGM
= 180° - 129° - 42°
= 9° (Angles sum of triangle)
(b)
∠GLK
= 360° - 292°
= 68° (Angles at a point)
∠GJK = ∠GLK = 68° (Rhombus)
∠HJK
= 68° - 42°
= 26°
Answer(s): (a) 9°; (b) 26°