PSLE TUVW and UWXY are rhombuses. VZW is a straight line.
- Find ∠WUZ.
- Find ∠VWX.
(a)
∠UWV
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠WUZ
= 180° - 121° - 37°
= 22° (Angles sum of triangle)
(b)
∠UYX
= 360° - 289°
= 71° (Angles at a point)
∠UWX = ∠UYX = 71° (Rhombus)
∠VWX
= 71° - 37°
= 34°
Answer(s): (a) 22°; (b) 34°