PSLE DEFG and EGHJ are rhombuses. FKG is a straight line.
- Find ∠GEK.
- Find ∠FGH.
(a)
∠EGF
= (180° - 102°) ÷2
= 78° ÷ 2
= 39° (Isosceles triangle)
∠GEK
= 180° - 130° - 39°
= 11° (Angles sum of triangle)
(b)
∠EJH
= 360° - 285°
= 75° (Angles at a point)
∠EGH = ∠EJH = 75° (Rhombus)
∠FGH
= 75° - 39°
= 36°
Answer(s): (a) 11°; (b) 36°