PSLE DEFG and EGHJ are rhombuses. FKG is a straight line.
- Find ∠GEK.
- Find ∠FGH.
(a)
∠EGF
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠GEK
= 180° - 121° - 37°
= 22° (Angles sum of triangle)
(b)
∠EJH
= 360° - 290°
= 70° (Angles at a point)
∠EGH = ∠EJH = 70° (Rhombus)
∠FGH
= 70° - 37°
= 33°
Answer(s): (a) 22°; (b) 33°