PSLE HJKL and JLMN are rhombuses. KPL is a straight line.
- Find ∠LJP.
- Find ∠KLM.
(a)
∠JLK
= (180° - 98°) ÷2
= 82° ÷ 2
= 41° (Isosceles triangle)
∠LJP
= 180° - 132° - 41°
= 7° (Angles sum of triangle)
(b)
∠JNM
= 360° - 299°
= 61° (Angles at a point)
∠JLM = ∠JNM = 61° (Rhombus)
∠KLM
= 61° - 41°
= 20°
Answer(s): (a) 7°; (b) 20°