PSLE DEFG and EGHJ are rhombuses. FKG is a straight line.
- Find ∠GEK.
- Find ∠FGH.
(a)
∠EGF
= (180° - 108°) ÷2
= 72° ÷ 2
= 36° (Isosceles triangle)
∠GEK
= 180° - 125° - 36°
= 19° (Angles sum of triangle)
(b)
∠EJH
= 360° - 305°
= 55° (Angles at a point)
∠EGH = ∠EJH = 55° (Rhombus)
∠FGH
= 55° - 36°
= 19°
Answer(s): (a) 19°; (b) 19°