PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 100°) ÷2
= 80° ÷ 2
= 40° (Isosceles triangle)
∠HFL
= 180° - 126° - 40°
= 14° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 282°
= 78° (Angles at a point)
∠FHJ = ∠FKJ = 78° (Rhombus)
∠GHJ
= 78° - 40°
= 38°
Answer(s): (a) 14°; (b) 38°