PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 100°) ÷2
= 80° ÷ 2
= 40° (Isosceles triangle)
∠HFL
= 180° - 128° - 40°
= 12° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 294°
= 66° (Angles at a point)
∠FHJ = ∠FKJ = 66° (Rhombus)
∠GHJ
= 66° - 40°
= 26°
Answer(s): (a) 12°; (b) 26°