PSLE FGHJ and GJKL are rhombuses. HMJ is a straight line.
- Find ∠JGM.
- Find ∠HJK.
(a)
∠GJH
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠JGM
= 180° - 130° - 37°
= 13° (Angles sum of triangle)
(b)
∠GLK
= 360° - 283°
= 77° (Angles at a point)
∠GJK = ∠GLK = 77° (Rhombus)
∠HJK
= 77° - 37°
= 40°
Answer(s): (a) 13°; (b) 40°