PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 106°) ÷2
= 74° ÷ 2
= 37° (Isosceles triangle)
∠HFL
= 180° - 130° - 37°
= 13° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 281°
= 79° (Angles at a point)
∠FHJ = ∠FKJ = 79° (Rhombus)
∠GHJ
= 79° - 37°
= 42°
Answer(s): (a) 13°; (b) 42°