PSLE HJKL and JLMN are rhombuses. KPL is a straight line.
- Find ∠LJP.
- Find ∠KLM.
(a)
∠JLK
= (180° - 104°) ÷2
= 76° ÷ 2
= 38° (Isosceles triangle)
∠LJP
= 180° - 125° - 38°
= 17° (Angles sum of triangle)
(b)
∠JNM
= 360° - 276°
= 84° (Angles at a point)
∠JLM = ∠JNM = 84° (Rhombus)
∠KLM
= 84° - 38°
= 46°
Answer(s): (a) 17°; (b) 46°