PSLE EFGH and FHJK are rhombuses. GLH is a straight line.
- Find ∠HFL.
- Find ∠GHJ.
(a)
∠FHG
= (180° - 110°) ÷2
= 70° ÷ 2
= 35° (Isosceles triangle)
∠HFL
= 180° - 123° - 35°
= 22° (Angles sum of triangle)
(b)
∠FKJ
= 360° - 304°
= 56° (Angles at a point)
∠FHJ = ∠FKJ = 56° (Rhombus)
∠GHJ
= 56° - 35°
= 21°
Answer(s): (a) 22°; (b) 21°