PSLEHJKL is a parallelogram, HKM is an equilateral triangle and KL = LM.
- Find ∠HKL.
- Find ∠KLH.
- Find ∠MHJ.
(a)
KL = LM
Triangle KLM is an isosceles triangle.
∠LKM
= (180° - 136°) ÷ 2
= 44° ÷ 2
= 22° (Isosceles triangle)
∠HKL
= 60° - 22°
= 38° (Equilateral triangle)
(b)
∠HML
= 60° - 22°
= 38° (Equilateral triangle)
∠HLM
= 180° - 38° - 22°
= 120° (Angles sum of triangle)
∠HLK
= 360° - 136° - 120°
= 104° (Angles at a point)
∠JHK
= ∠HKL
= 38° (Alternate angles)
∠JHM
= 60° + 38°
= 98°
Answer(s): (a) 38°; (b) 104°; (c) 98°
