PSLEGHJK is a parallelogram, GJL is an equilateral triangle and JK = KL.
- Find ∠GJK.
- Find ∠JKG.
- Find ∠LGH.
(a)
JK = KL
Triangle JKL is an isosceles triangle.
∠KJL
= (180° - 148°) ÷ 2
= 32° ÷ 2
= 16° (Isosceles triangle)
∠GJK
= 60° - 16°
= 44° (Equilateral triangle)
(b)
∠GLK
= 60° - 16°
= 44° (Equilateral triangle)
∠GKL
= 180° - 44° - 16°
= 120° (Angles sum of triangle)
∠GKJ
= 360° - 148° - 120°
= 92° (Angles at a point)
∠HGJ
= ∠GJK
= 44° (Alternate angles)
∠HGL
= 60° + 44°
= 104°
Answer(s): (a) 44°; (b) 92°; (c) 104°
