The figure shows the amount of water in two rectangular tanks, H and J, at first. Rael poured
14 of the water from H into J to fill it to the top, without overflowing.
- How much water was there in Tank H at first?
- Rael then poured all the water from Tank J into Tank H. 4554 cm3 of water overflowed from Tank H. What was the height of Tank H?
(a)
Volume of water to fill Tank J
= 18 x 15 x 15
= 4050 cm
3
14 of volume of water in Tank H at first = 4050 cm
3
44 of volume of water in Tank H at first = 4 x 4050 = 16200 cm
3 Volume of water in Tank H at first = 16200 cm
3 Volume of water in Tank J at first
= 18 x 15 x 17
= 4590 cm
3 Total volume of water in Tank H and Tank J
= 16200 + 4590
= 20790 cm
3 Final volume of water in Tank H after 4554 cm
3 of water overflowed
= 20790 - 4554
= 16236 cm
3 Base area of Tank H
= 22 x 18
= 396 cm
2 Height of Tank H
= 16236 ÷ 396
= 41 cm
Answer(s): (a) 16200 cm
2 ; (b) 41 cm