The figure shows the amount of water in two rectangular tanks, L and M, at first. Caden poured
13 of the water from L into M to fill it to the top, without overflowing.
- How much water was there in Tank L at first?
- Caden then poured all the water from Tank M into Tank L. 480 cm3 of water overflowed from Tank L. What was the height of Tank L?
(a)
Volume of water to fill Tank M
= 20 x 16 x 15
= 4800 cm
3
13 of volume of water in Tank L at first = 4800 cm
3
33 of volume of water in Tank L at first = 3 x 4800 = 14400 cm
3 Volume of water in Tank L at first = 14400 cm
3 Volume of water in Tank M at first
= 20 x 16 x 18
= 5760 cm
3 Total volume of water in Tank L and Tank M
= 14400 + 5760
= 20160 cm
3 Final volume of water in Tank L after 480 cm
3 of water overflowed
= 20160 - 480
= 19680 cm
3 Base area of Tank L
= 24 x 20
= 480 cm
2 Height of Tank L
= 19680 ÷ 480
= 41 cm
Answer(s): (a) 14400 cm
2 ; (b) 41 cm