The figure shows the amount of water in two rectangular tanks, N and P, at first. Dylan poured ¹₄ of the water from N into P to fill it to the top, without overflowing.

1. How much water was there in Tank N at first?
2. Dylan then poured all the water from Tank P into Tank N. 6536 cm³ of water overflowed from Tank N. What was the height of Tank N?

(a)
Volume of water to fill Tank P
= 19 x 16 x 18
= 5472 cm<sup>3

1</sup>₄ of volume of water in Tank N at first = 5472 cm^3  
4₄ of volume of water in Tank N at first = 4 x 5472 = 21888 cm³

Volume of water in Tank N at first = 21888 cm³

Volume of water in Tank P at first
= 19 x 16 x 20
= 6080 cm³

Total volume of water in Tank N and Tank P 
= 21888 + 6080
= 27968 cm³

Final volume of water in Tank N after 6536 cm³ of water overflowed
= 27968 - 6536
= 21432 cm³

Base area of Tank N
= 24 x 19
= 456 cm²

Height of Tank N
= 21432 ÷ 456 
= 47 cm

Answer(s): (a) 21888 cm² ; (b) 47 cm