The figure shows the amount of water in two rectangular tanks, P and Q, at first. Xavier poured
14 of the water from P into Q to fill it to the top, without overflowing.
- How much water was there in Tank P at first?
- Xavier then poured all the water from Tank Q into Tank P. 2628 cm3 of water overflowed from Tank P. What was the height of Tank P?
(a)
Volume of water to fill Tank Q
= 18 x 14 x 15
= 3780 cm
3
14 of volume of water in Tank P at first = 3780 cm
3
44 of volume of water in Tank P at first = 4 x 3780 = 15120 cm
3 Volume of water in Tank P at first = 15120 cm
3 Volume of water in Tank Q at first
= 18 x 14 x 18
= 4536 cm
3 Total volume of water in Tank P and Tank Q
= 15120 + 4536
= 19656 cm
3 Final volume of water in Tank P after 2628 cm
3 of water overflowed
= 19656 - 2628
= 17028 cm
3 Base area of Tank P
= 22 x 18
= 396 cm
2 Height of Tank P
= 17028 ÷ 396
= 43 cm
Answer(s): (a) 15120 cm
2 ; (b) 43 cm