The figure shows the amount of water in two rectangular tanks, H and J, at first. George poured
14 of the water from H into J to fill it to the top, without overflowing.
- How much water was there in Tank H at first?
- George then poured all the water from Tank J into Tank H. 4288 cm3 of water overflowed from Tank H. What was the height of Tank H?
(a)
Volume of water to fill Tank J
= 16 x 14 x 13
= 2912 cm
3
14 of volume of water in Tank H at first = 2912 cm
3
44 of volume of water in Tank H at first = 4 x 2912 = 11648 cm
3 Volume of water in Tank H at first = 11648 cm
3 Volume of water in Tank J at first
= 16 x 14 x 16
= 3584 cm
3 Total volume of water in Tank H and Tank J
= 11648 + 3584
= 15232 cm
3 Final volume of water in Tank H after 4288 cm
3 of water overflowed
= 15232 - 4288
= 10944 cm
3 Base area of Tank H
= 18 x 16
= 288 cm
2 Height of Tank H
= 10944 ÷ 288
= 38 cm
Answer(s): (a) 11648 cm
2 ; (b) 38 cm